A certain cross section lies in the x-y plane. If 3×10^20 electrons go through the cross section in the z-direction in 4 seconds, and simultaneously 1.5×10^20 protons go through the same cross section in the negative z-direction, what is the magnitude and direction of the current flowing through the cross section? Current is given asI = q (charge) / t (time)And the flow of current is due to the movement of electrons.So total charge = 3 x 1020 CAnd Time = 4 sec Therefore, I = 3 x 1020 / 4 AmpereI = 0.75…
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